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Procs

proc cyclicTree(n: PNode): bool {...}{.raises: [], tags: [].}
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proc exprStructuralEquivalent(a, b: PNode; strictSymEquality = false): bool {...}{.
    raises: [], tags: [].}
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proc sameTree(a, b: PNode): bool {...}{.raises: [], tags: [].}
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proc getMagic(op: PNode): TMagic {...}{.raises: [], tags: [].}
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proc isConstExpr(n: PNode): bool {...}{.raises: [], tags: [].}
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proc isCaseObj(n: PNode): bool {...}{.raises: [], tags: [].}
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proc isDeepConstExpr(n: PNode; preventInheritance = false): bool {...}{.raises: [],
    tags: [].}
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proc isRange(n: PNode): bool {...}{.inline, raises: [], tags: [].}
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proc whichPragma(n: PNode): TSpecialWord {...}{.raises: [], tags: [].}
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proc isNoSideEffectPragma(n: PNode): bool {...}{.raises: [], tags: [].}
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proc findPragma(n: PNode; which: TSpecialWord): PNode {...}{.raises: [], tags: [].}
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proc effectSpec(n: PNode; effectType: TSpecialWord): PNode {...}{.raises: [],
    tags: [].}
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proc propSpec(n: PNode; effectType: TSpecialWord): PNode {...}{.raises: [], tags: [].}
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proc flattenStmts(n: PNode): PNode {...}{.raises: [], tags: [].}
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proc extractRange(k: TNodeKind; n: PNode; a, b: int): PNode {...}{.raises: [],
    tags: [].}
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proc isTrue(n: PNode): bool {...}{.raises: [], tags: [].}
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proc getRoot(n: PNode): PSym {...}{.raises: [], tags: [].}
getRoot takes a path n. A path is an lvalue expression like obj.x[i].y. The root of a path is the symbol that can be determined as the owner; obj in the example.   Source Edit
proc stupidStmtListExpr(n: PNode): bool {...}{.raises: [], tags: [].}
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proc dontInlineConstant(orig, cnst: PNode): bool {...}{.inline, raises: [], tags: [].}
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